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8120=x^2-10x+45
We move all terms to the left:
8120-(x^2-10x+45)=0
We get rid of parentheses
-x^2+10x-45+8120=0
We add all the numbers together, and all the variables
-1x^2+10x+8075=0
a = -1; b = 10; c = +8075;
Δ = b2-4ac
Δ = 102-4·(-1)·8075
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-180}{2*-1}=\frac{-190}{-2} =+95 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+180}{2*-1}=\frac{170}{-2} =-85 $
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